JEE Main & Advanced Mathematics Limits, Continuity and Differentiability Question Bank Self Evaluation Test - Continuity and Differentiability

  • question_answer
    If \[f(xy)=f(x).f(y)\] for all x, y and f(x) is continuous at x = 2, then f(x) is not necessarily continuous in:

    A) \[(-\infty ,\infty )\]

    B) \[(0,\infty )\]

    C) \[(-\infty ,0)\]

    D) \[(2,\infty )\]

    Correct Answer: A

    Solution :

    [a] Given, \[f(xy)=f(x).f(y)\] for all x, y,     ?.(1)
    \[f(x)\] is continuous at x = 2,
    i.e.,\[\underset{x\to 2}{\mathop{Lt}}\,\,\,f(x)=f(2)...(2)\]
    Let \[a\ne 0\]
    Now,     \[\underset{x\to a}{\mathop{Lt}}\,\,\,f(x)=\underset{h\to 2}{\mathop{Lt}}\,\,f\left( \frac{ah}{2} \right)\]
                \[\left[ putting\,\,x=\frac{ah}{2}so\,\,that\,\,h=\frac{2x}{a} \right]\]
    \[=f\left( \frac{a}{2} \right)\underset{h\to 2}{\mathop{Lt}}\,f(h)=f\left( \frac{a}{2} \right).f(2)=f\left( \frac{a}{2}.2 \right)=f(a)\]
    Hence, \[f(x)\] is necessarily continuous at x = a for all \[a\ne 0\].
    At x = 0, f(x) may or may not be continuous
    Hence f(x) is not necessarily continuous in\[(-\infty ,+\infty )\].


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