A) \[\left\{ 0,1 \right\}\]
B) \[\left\{ 0,-1 \right\}\]
C) \[\left\{ 0,1,-1 \right\}\]
D) None of these
Correct Answer: C
Solution :
[c] Given that \[f(x)=\left| 1-x \right|\] \[\therefore f(\left| x \right|)=\left\{ \begin{matrix} x-1, & x>1 \\ 1-x, & 0<x\le 1 \\ 1+x, & -1\le x\le 0 \\ -x-1, & x<-1 \\ \end{matrix} \right.\] Clearly, the domain of \[{{\sin }^{-1}}(f\left| x \right|)\] is \[[-2,2]\]. Therefore, it is non-differentiable at the points \[\{-1,0,1\}\].
You need to login to perform this action.
You will be redirected in
3 sec
