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JEE Main & Advanced Mathematics Limits, Continuity and Differentiability Question Bank Self Evaluation Test - Continuity and Differentiability

  • question_answer
    Let \[f(x)=[{{x}^{3}}-3],[x]=\]G.I.F. Then the no. of points in the interval (1, 2) where function is discontinuous is

    A) 5

    B) 4

    C) 6

    D) 3

    Correct Answer: C

    Solution :

    [c] \[f(x)=[{{x}^{3}}-3]\] \[{{(1.26)}^{3}}=2-3=-1;{{(1.44)}^{3}}=3-3=0\] Similarly, we can check for other points where \[f(x)\] changes values to 1, 2, 3, 4. \[\therefore \] Total number of points of discontinuity are ?6?.


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