A) \[f(x)\] is differentiable everywhere
B) \[f(x)\] is not differentiable at x = 0
C) \[f(x)\ge 1\] for all \[x\in R\]
D) \[f(x)\] is not differentiable at \[x=1\]
Correct Answer: A
Solution :
[a] \[f(x)=\min \{x+1,\left| x \right|+1\}\] \[\Rightarrow f(x)=x+1\forall x\in R\] Hence, \[f(x)\] is differentiable everywhere for all \[x\in R\].You need to login to perform this action.
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