A) 6/5
B) 5/4
C) 4/3
D) 7/6
Correct Answer: B
Solution :
[b] Let \[f(x)={{x}^{2}}-2x+3\] Since, \[f'(c)=\frac{f\left( \frac{3}{2} \right)-f(1)}{\frac{3}{2}-1}\] (given) \[\Rightarrow 2c-2=\frac{\frac{9}{4}-\frac{6}{2}+3-(1-2+3)}{\frac{3}{2}-1}\Rightarrow c=\frac{5}{4}\]You need to login to perform this action.
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