A) 5
B) 4
C) 6
D) 3
Correct Answer: C
Solution :
[c] \[f(x)=[{{x}^{3}}-3]\] \[{{(1.26)}^{3}}=2-3=-1;{{(1.44)}^{3}}=3-3=0\] Similarly, we can check for other points where \[f(x)\] changes values to 1, 2, 3, 4. \[\therefore \] Total number of points of discontinuity are ?6?.You need to login to perform this action.
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