A) \[\frac{1}{s}\]
B) \[\frac{1}{{{s}^{2}}}\]
C) \[\frac{1}{{{s}^{3}}}\]
D) \[\frac{1}{{{s}^{4}}}\]
Correct Answer: C
Solution :
[c] \[s=\sqrt{{{t}^{2}}+1}\] \[\Rightarrow \frac{ds}{dt}=\frac{t}{\sqrt{{{t}^{2}}+1}}\Rightarrow \frac{{{d}^{2}}s}{d{{t}^{2}}}=\frac{1}{\sqrt{{{\left( {{t}^{2}}+1 \right)}^{3}}}}\] \[\Rightarrow \frac{{{d}^{2}}s}{d{{t}^{2}}}=\frac{1}{{{s}^{3}}}\]You need to login to perform this action.
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