A) -1
B) 0
C) 1
D) Derivative does not exist
Correct Answer: C
Solution :
[c] \[f(x)=\left| x-1 \right|\] Redefined the function \[f(x)\] \[f(x)=\left\{ \begin{matrix} 1-x, & x<1 \\ x-1, & x>1 \\ \end{matrix} \right.\] \[f'(x)=\left\{ \begin{matrix} -1; & x<1 \\ 1; & x>1 \\ \end{matrix} \right.\] \[\therefore f'(2)=1\]You need to login to perform this action.
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