JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Self Evaluation Test - Current Electricity

  • question_answer
    A battery of emf \[{{E}_{0}}=6V\] is connected across a 2m long uniform wire having resistance \[4\Omega /m.\] The cell of small emf \[{{\varepsilon }_{1}}=2V\] and \[{{\varepsilon }_{2}}=3V\] having internal resistance \[2\Omega \,\And \,1\Omega \] respectively are connected as show in the figure. The null point will be obtained at                        

    A) 0.10m

    B) 0.25m

    C) 0.50m

    D) 0.75m

    Correct Answer: D

    Solution :

    [d] Effective emf of two cells in parallel \[\varepsilon =\frac{{{\varepsilon }_{2}}{{r}_{1}}-{{\varepsilon }_{1}}{{r}_{2}}}{{{r}_{1}}+{{r}_{2}}}=\frac{3\times 2-2\times 1}{2+1}=\frac{4}{3}V\] X terminal of the connection is positive. For neutral point, positive terminal of\[{{\varepsilon }_{0}}\]must be connected to X.


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