A)
B)
C)
D)
Correct Answer: B
Solution :
[b] Current in the circuit, \[I=\frac{\varepsilon }{R+r}\] Potential difference across R, \[V=IR=\left( \frac{\varepsilon }{R+r} \right)R=\frac{\varepsilon }{1+\frac{r}{R}}\] When \[R=0,V=0\] \[R=\infty ,V=\varepsilon \]You need to login to perform this action.
You will be redirected in
3 sec