A) \[\frac{1}{3}A\]and 3 V
B) \[\frac{1}{6}A\] and 4 V
C) \[\frac{1}{9}A\] and 9 V
D) \[\frac{1}{12}A\] and 12 V
Correct Answer: A
Solution :
[a] \[I=\frac{8-4}{1+2+9}=\frac{4}{12}=\frac{1}{3}A;\] \[{{V}_{P}}-{{V}_{Q}}=4-\frac{1}{3}\times 3=3volt\]You need to login to perform this action.
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