A) The value of \[{{\varepsilon }_{1}}\]will be \[\frac{\varepsilon \left( R+r \right)}{R}\]
B) Current in R is \[\frac{\varepsilon {{ }_{1}}}{r+R}\]
C) Value of \[\varepsilon {{ }_{1}}\], will be\[\varepsilon \]
D) Potential across 2R is zero.
Correct Answer: C
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