JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Self Evaluation Test - Current Electricity

  • question_answer
    The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of \[10\Omega \]is

    A) \[0.5\Omega \]

    B) \[0.8\Omega \]

    C) \[1.0\Omega \]

    D) \[0.2\Omega \]

    Correct Answer: A

    Solution :

    [a] Given: emf \[\varepsilon =2.1V\] \[I=0.2A,R=10\Omega \] Internal resistance \[r=?\] From formula. \[\varepsilon -Ir=V=IR\] \[2.1-0.2r=0.2\times 10\] \[2.1-0.2r=2\text{ or }0.2r=0.1\] \[\Rightarrow r=\frac{0.1}{0.2}=0.5\Omega \]


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