A) zero
B) 1V
C) 2V
D) (2/3)V
Correct Answer: A
Solution :
[a] \[{{E}_{net}}=\frac{{{E}_{1}}{{r}_{2}}-{{E}_{2}}{{r}_{1}}}{{{r}_{1}}+{{r}_{2}}}\text{ or }{{E}_{net}}=\frac{2-2}{2+1}=0\]
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