JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Self Evaluation Test - Current Electricity

  • question_answer
    Two batteries of emf 4 V and 8 V with internal resistance \[1\Omega \] and \[2\Omega \]are connected in a circuit with a resistance of \[9\Omega \] as shown in figure. The current and potential difference between the points P and Q are

    A) \[\frac{1}{3}A\]and 3 V

    B) \[\frac{1}{6}A\] and 4 V

    C) \[\frac{1}{9}A\] and 9 V

    D) \[\frac{1}{12}A\] and 12 V

    Correct Answer: A

    Solution :

    [a] \[I=\frac{8-4}{1+2+9}=\frac{4}{12}=\frac{1}{3}A;\] \[{{V}_{P}}-{{V}_{Q}}=4-\frac{1}{3}\times 3=3volt\]


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