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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Self Evaluation Test - Current Electricity

  • question_answer
    A electric tea kettle has two heating coils. When first coil of resistance \[{{R}_{1}}\]is switched on, the kettle begins to boil tea in 6 minutes. When second coil of resistance \[{{R}_{2}}\]is switched on, the boiling begins in 8 minutes. The value of \[{{R}_{1}}/{{R}_{2}}\]is

    A) \[\frac{7}{3}\]

    B) \[\frac{3}{7}\]

    C) \[\frac{3}{4}\]

    D) \[\frac{4}{3}\]

    Correct Answer: C

    Solution :

    [c] Heat supplied \[=\frac{{{V}^{2}}}{R}\times t\] \[\Rightarrow \frac{{{t}_{1}}}{{{R}_{1}}}=\frac{{{t}_{2}}}{{{R}_{2}}}\Rightarrow \frac{6}{{{R}_{1}}}=\frac{8}{{{R}_{2}}}\Rightarrow \frac{{{R}_{1}}}{{{R}_{2}}}=\frac{3}{4}\]


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