A) 4.00
B) 2.00
C) 0.50
D) 0.25
Correct Answer: A
Solution :
[a] \[H={{I}^{2}}Rt.\text{ Here }{{R}_{1}}=\rho \frac{1}{\pi {{r}^{2}}}\text{ and }\] \[{{R}_{2}}=\rho \frac{1}{\pi {{\left( 2r \right)}^{2}}}\text{ That is, }{{R}_{1}}=4{{R}_{2}}.\] \[\text{Hence, }\frac{{{H}_{1}}}{{{H}_{2}}}=4\]
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