JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Self Evaluation Test - Current Electricity

  • question_answer
    Two cities are 150 km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8 volt and the average resistance per km is \[0.5\Omega \]. The power loss in the wires is:

    A) 19.2 W

    B) 19.2 kW

    C) 19.2 J

    D) 12.2 kW

    Correct Answer: B

    Solution :

    [b] Total resistance \[R=\left( 0.5\text{ }\Omega /km \right)\times \left( 150km \right)=75\Omega \] Total voltage drop \[=\left( 8V/km \right)\times \left( 150km \right)=1200V\] Power loss \[~=\frac{{{\left( \Delta V \right)}^{2}}}{R}=\frac{{{\left( 1200 \right)}^{2}}}{75}W\] \[=19200W=19.2kW\]


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