A) \[10\Omega \]
B) \[15\Omega \]
C) \[20\Omega \]
D) \[25\Omega \]
Correct Answer: B
Solution :
[b] This is a balanced Wheatstone bridge condition, \[\frac{5}{R}=\frac{{{\ell }_{1}}}{100-{{\ell }_{1}}}\text{ and }\frac{5}{R/2}=\frac{1.6{{\ell }_{1}}}{100-1.6{{\ell }_{1}}}\] \[\Rightarrow R=15\Omega \]
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