A) \[0.8\Omega \]
B) \[0.5\Omega \]
C) \[0.4\Omega \]
D) \[0.25\Omega \]
Correct Answer: D
Solution :
[d] \[\frac{P}{Q}=\frac{l}{\left( 100-l \right)}\] \[\text{or }P=\frac{l}{100-l}\times Q=\frac{20}{80}\times I=0.25\Omega .\]
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