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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Self Evaluation Test - Current Electricity

  • question_answer
    A potentiometer arrangement is shown in fig. The driver cell has emf e and internal resistance r. The resistance of potentiometer wire AB is R. F is the cell of em e/3 and internal resistance r/3. Balance point (J) can be obtained for all finite values of

    A) R>r/2

    B) R<r/2

    C) R>r/3

    D) R<r/3

    Correct Answer: A

    Solution :

    [a] Current in \[AB=I=\frac{e}{R+r}\] potential difference across \[\] To obtain balanced point, \[\frac{eR}{R+r}>\frac{e}{3}\text{ or }R>r/2\]


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