A) \[1\]
B) \[4\]
C) \[3\]
D) \[0\]
Correct Answer: D
Solution :
[d] If the G.P be \[a,ar,a{{r}^{2}},....\] then \[{{a}_{n}}=a{{r}^{n-1}}\] \[{{R}_{3}}\to {{R}_{3}}-{{R}_{2}}\] and \[{{R}_{2}}\to {{R}_{2}}-{{R}_{1}}\] gives, \[=\left| \begin{matrix} \log a+(n-1)log\,r & \log a+n\log r & \log a+(n+1)log\,r \\ \log \,r & lor\,r & \log \,r \\ \log \,r & \log \,r & \log \,r \\ \end{matrix} \right|\] = 0, since \[{{R}_{2}}\] and \[{{R}_{3}}\] are identical.You need to login to perform this action.
You will be redirected in
3 sec