A) \[[z]\]
B) \[[y]\]
C) [x]
D) None of these
Correct Answer: A
Solution :
[a] Since, \[-1<x<0\] \[\therefore \,\,\,\,[x]=-1\] \[0<y<1\,\,\,\,\,\,\,\,\,\,\,\therefore \,\,[y]=0,\] \[1<z<2\,\,\,\,\,\,\,\,\,\,\therefore \,[z]=1\] \[\therefore \] Given determinant \[=\left| \begin{matrix} 0 & 0 & 1 \\ -1 & 1 & 1 \\ -1 & 0 & 2 \\ \end{matrix} \right|=1=[z]\]You need to login to perform this action.
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