A) 0
B) 1
C) 2
D) infinite
Correct Answer: B
Solution :
[b] For infinitely many solutions the two equations become identical \[\Rightarrow \,\,\,\frac{k+1}{k}=\frac{8}{k+3}=\frac{4k}{3k-1}\Rightarrow k=1\]You need to login to perform this action.
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