JEE Main & Advanced Mathematics Differential Equations Question Bank Self Evaluation Test - Differential Equations

  • question_answer
    The solution of differential equation\[yy'=x\left( \frac{{{y}^{2}}}{{{x}^{2}}}+\frac{f({{y}^{2}}/{{x}^{2}})}{f'({{y}^{2}}/{{x}^{2}})} \right)\] is

    A) \[f({{y}^{2}}/{{x}^{2}})=c{{x}^{2}}\]

    B) \[{{x}^{2}}f({{y}^{2}}/{{x}^{2}})={{c}^{2}}{{y}^{2}}\]

    C) \[{{x}^{2}}f({{y}^{2}}/{{x}^{2}})=c\]

    D) \[f({{y}^{2}}/{{x}^{2}})=cy/x\]

    Correct Answer: A

    Solution :

    [a] The given equation can be written as
    \[\frac{y}{x}\frac{dy}{dx}=\left\{ \frac{{{y}^{2}}}{{{x}^{2}}}+\frac{f({{y}^{2}}/{{x}^{2}})}{f'({{y}^{2}}/{{x}^{2}})} \right\}\]
    The above equation is a homogeneous equation.
    Putting \[y=vx,\]we get
    \[v\left[ v+x\frac{dv}{dx} \right]={{v}^{2}}+\frac{f({{v}^{2}})}{f'({{v}^{2}})}\]
    or \[vx\frac{dv}{dx}=\frac{f({{v}^{2}})}{f'({{v}^{2}})}\]        (variable separable)
    or \[\frac{2vf'({{v}^{2}})}{f({{v}^{2}})}dv=2\frac{dx}{x}\]
    Now, integrating both sides, we get
    \[\log f({{v}^{2}})=log{{x}^{2}}+\log c[logc=constant]\]
    or \[\log f({{v}^{2}})=logc{{x}^{2}}orf({{v}^{2}})=c{{x}^{2}}\] or
    \[f({{y}^{2}}/{{x}^{2}})=c{{x}^{2}}\]


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