A) \[\frac{h}{\sqrt{3\,mk\,T}}\]
B) \[\frac{2\,h}{\sqrt{3\,mk\,T}}\]
C) \[\frac{2\,h}{\sqrt{mk\,T}}\]
D) \[\frac{h}{\sqrt{mk\,T}}\]
Correct Answer: A
Solution :
[a] We know that, de-Broglie wavelength \[\lambda =\frac{h}{p}=\frac{h}{\sqrt{2m\left( KE \right)}}\] K.E. of thermal neutron \[=\frac{3}{2}kT\] \[=\frac{h}{\sqrt{2m\left( \frac{3}{2}kT \right)}}\Rightarrow \lambda =\frac{h}{\sqrt{3mkT}}\]
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