A) \[\text{4077}\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[992\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[628\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[238\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: A
Solution :
[a] By Einstein equation \[hf={{W}_{0}}+e{{V}_{0}}.\] \[{{W}_{0}}=\frac{hc}{\lambda }-e{{V}_{0}}\] \[=\frac{\left( 6.63\times {{10}^{-34}} \right)\times \left( 3\times {{10}^{8}} \right)}{4950\times {{10}^{-10}}}-\left( 1.6\times {{10}^{-19}} \right)\times 0.6\] \[=3.12\times {{10}^{-19}}J\] For the second surface \[hf'={{W}_{0}}+e{{V}_{0}}\] \[\text{or }\frac{hc}{\lambda '}=3.2\times {{10}^{-19}}+1.6\times {{10}^{-19}}\times 1.1\]\[\therefore \lambda '=4077\overset{\text{o}}{\mathop{\text{A}}}\,\]
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