A) \[\frac{-h}{eE{{t}^{2}}}\]
B) \[\frac{-eht}{E}\]
C) \[\frac{-mh}{eE{{t}^{2}}}\]
D) \[\frac{-h}{eE}\]
Correct Answer: A
Solution :
[a] Acceleration, \[a=\frac{Ee}{m}\] Velocity of electron, \[v=at=\frac{Eet}{m}\] Wavelength, \[\lambda =\frac{h}{mv}=\frac{h}{Eet}.\] Now \[\frac{d\lambda }{dt}=-\frac{h}{eE{{t}^{2}}}\]You need to login to perform this action.
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