A) \[N=P\lambda {{d}^{2}}t/hc{{l}^{2}}\]
B) \[N=4P\lambda {{d}^{2}}t/hc{{l}^{2}}\]
C) \[N=P\lambda {{d}^{2}}t/4hc{{l}^{2}}\]
D) \[N=P\lambda {{d}^{2}}t/16hc{{l}^{2}}\]
Correct Answer: A
Solution :
[a] \[E=\frac{hc}{\lambda }\] Number of photons emitted is \[\frac{Pt}{\left( \frac{hc}{\lambda } \right)}={{n}_{0}}\text{ }{{n}_{0}}=\frac{P\lambda t}{hc}\] Since the radiation is spherically symmetric, so total number of photons entering the sensor is \[{{n}_{0}}\] times the ratio of aperture area to the area of a sphere of radius l. \[N={{n}_{0}}\frac{\pi {{\left( 2d \right)}^{2}}}{4\pi {{l}^{2}}}=\frac{P\lambda t}{hc}\frac{{{d}^{2}}}{{{l}^{2}}}\]
You need to login to perform this action.
You will be redirected in
3 sec
