A) 1.24keV
B) 12.4keV
C) 124keV
D) None of these
Correct Answer: B
Solution :
[b] \[{{\lambda }_{\min }}=1\overset{\text{o}}{\mathop{\text{A}}}\,\] (given) \[\therefore {{\lambda }_{\min }}=\frac{1240}{E}(eV)(nm)\] \[\text{Thus, }E=\frac{1240(eV)(nm)}{0.01(nm)}=12400eV\] \[E=12.4KeV\]
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