A) 200P
B) 400P
C) \[\frac{P}{200}\]
D) 100P
Correct Answer: A
Solution :
[a] The de-Broglie's wavelength associated with the moving electron \[\lambda =\frac{h}{p}\] Now, according to problem \[\frac{d\lambda }{\lambda }=-\frac{dp}{P};\text{ }\frac{0.5}{100}=\frac{P}{P'}\Rightarrow P'=200P\]You need to login to perform this action.
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