A) \[1.32\times {{10}^{15}}Hz\]
B) \[3.28\times {{10}^{14}}Hz\]
C) \[6.22\times {{10}^{15}}Hz\]
D) \[2.22\times {{10}^{11}}Hz\]
Correct Answer: A
Solution :
[a] The work function of the metal \[{{W}_{0}}=h{{f}_{0}}=(6.63\times {{10}^{-34}})\times (6\times {{10}^{14}})\] \[=3.98\times {{10}^{19}}J\] If f is the frequency of the light, then \[hc={{W}_{0}}+e{{V}_{0}}\] \[=\frac{3.98\times {{10}^{-19}}+1.6\times {{10}^{-19}}\times 3}{6.63\times {{10}^{-34}}}=1.32\times {{10}^{15}}Hz\]You need to login to perform this action.
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