A) \[7.26\times {{10}^{7}}m/s\]
B) \[7.62\times {{10}^{7}}m/s\]
C) \[7.62\times {{10}^{7}}cm/s\]
D) \[7.26\times {{10}^{9}}m/s.\]
Correct Answer: A
Solution :
[a] The maximum kinetic energy of an electron accelerated through a potential difference of V volt is \[\frac{1}{2}m{{v}^{2}}=eV\] \[\therefore \]Maximum velocity \[v=\sqrt{\frac{2eV}{m}}\] \[v=\sqrt{\frac{2\times 1.6\times {{10}^{-19}}\times 15000}{9.1\times {{10}^{-31}}}},\] \[v=7.26\times {{10}^{7}}m/s\]
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