A) \[4\lambda \]
B) \[5\lambda \]
C) \[\frac{5}{2}\lambda \]
D) \[3\lambda \]
Correct Answer: D
Solution :
[d] According to Einstein's photoelectric effect, \[eV=\frac{hc}{\lambda }-\frac{hc}{{{\lambda }_{0}}}\] ?.(i) \[eV/4=\frac{hc}{2\lambda }-\frac{hc}{{{\lambda }_{0}}}\] ?(ii) Dividing equation (i) by (ii) by \[\Rightarrow 4=\frac{\frac{1}{\lambda }-\frac{1}{{{\lambda }_{0}}}}{\frac{1}{2\lambda }-\frac{1}{{{\lambda }_{0}}}}\]on solving we get, \[{{\lambda }_{0}}=3\lambda \]
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