question_answer

An electron microscope uses electrons accelerated by a voltage of 50 kV. If \[\lambda \] be the de-Broglie wavelength associated with the electrons. Also taking other factors, such as numerical aperture etc. to be same, the resolving power of an electron microscope be Re & that of an optical microscope which used yellow light is

A) \[\lambda =0.05\overset{\text{o}}{\mathop{\text{A}}}\,,{{R}_{e}}>>{{R}_{o}}\]         

B) \[\lambda =0.15\overset{\text{o}}{\mathop{\text{A}}}\,,{{R}_{e}}<<{{R}_{o}}\]

C) \[\lambda =0.11\overset{\text{o}}{\mathop{\text{A}}}\,,{{R}_{e}}<{{R}_{o}}\]

D) None of these