A) \[\sqrt{hv/m}\]
B) \[\sqrt{2hv/m}\]
C) \[2\sqrt{hv/m}\]
D) \[\sqrt{hv/\left( 2m \right)}\]
Correct Answer: B
Solution :
[b] From photo-electric equation, \[hv'=hv+{{K}_{\max }}\] ?.(i) \[2.hv=hv+\frac{1}{2}mV_{\max }^{2}\text{ }\left[ \therefore v'=2v \right]\]\[\Rightarrow hv=\frac{1}{2}mV_{\max }^{2}\Rightarrow {{V}_{\max }}=\sqrt{\frac{2hv}{m}}\]
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