JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Self Evaluation Test - Dual Nature of Radiation and Matter

  • question_answer
    A 200 W sodium street lamp emits yellow light of wavelength \[0.6\,\mu m\]. Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is

    A) \[1.5\times {{10}^{20}}\]

    B) \[6\times {{10}^{18}}\]

    C) \[62\times {{10}^{20}}\]

    D) \[3\times {{10}^{19}}\]

    Correct Answer: A

    Solution :

    [a] Give that, only 25% of 200W converter electrical energy into light of yellow color \[\left( \frac{hc}{\lambda } \right)\times N=200\times \frac{25}{100}\] Where N is the No. of photons emitted per second, h = plank's constant, c, speed of light. \[N=\frac{200\times 25}{100}\times \frac{\lambda }{hc}\] \[=\frac{200\times 25\times 0.6\times {{10}^{-6}}}{100\times 6.2\times {{10}^{-34}}\times 3\times {{10}^{8}}}=1.5\times {{10}^{20}}\]


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