A) \[6\times {{10}^{18}}\]
B) \[7\times {{10}^{19}}\]
C) \[8\times {{10}^{20}}\]
D) \[9\times {{10}^{21}}\]
Correct Answer: A
Solution :
[a] Number of protons \[=\frac{1C}{1.66\times {{10}^{-19}}C}\approx 6\times {{10}^{8}}\]
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