2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Electrostatics & Capacitance

JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electric Chages and Fields

  • question_answer
    The force of repulsion between two electrons at a certain distance is F. The force between two protons separated by the same distance is \[({{m}_{p}}=1836{{m}_{e}})\]

    A) 2F

    B) F    

    C) 1836F

    D) \[\frac{F}{1836}\]

    Correct Answer: B

    Solution :

    [b] Electrostatic force is given by \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] Here, charge and distance are same. So, force between two protons will be same.


You need to login to perform this action.
You will be redirected in 3 sec spinner