question_answer

Force between two identical charges placed at a distance of r in vacuum is F, Now a slab of dielectric of dielectric contrant 4 is inserted between these two charges. If the thickness of the slab is r/2, then the force between the charges will become

A) F

B) \[\frac{3}{5}F\]

C) \[\frac{4}{9}F\]

D) \[\frac{F}{2}\]