JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Self Evaluation Test - Electric Chages and Fields

  • question_answer
    ABC is an equilateral triangle. Charges +q are placed at each corner as shown in fig. The electric intensity at center O will be

    A) \[\frac{1}{4\pi {{\in }_{0}}}\frac{q}{r}\]

    B) \[\frac{1}{4\pi {{\in }_{0}}}\frac{q}{{{r}^{2}}}\]

    C) \[\frac{1}{4\pi {{\in }_{0}}}\frac{3q}{{{r}^{2}}}\]

    D) Zero

    Correct Answer: D

    Solution :

    [d] Unit positive charge at 0 will be repelled equally by three charges at the three corners of triangle. By symmetry, relsultant \[\vec{E}\] at O would be zero.


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