A) \[\frac{\lambda }{2\pi {{\varepsilon }_{0}}a}\]
B) 0
C) \[\frac{\lambda }{\pi {{\varepsilon }_{0}}a}\]
D) \[\frac{\lambda }{4\pi {{\varepsilon }_{0}}a}\]
Correct Answer: A
Solution :
[a] The field at O due to small element \[dx\] is \[dE=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{\lambda dx}{{{x}^{2}}}\]You need to login to perform this action.
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