A) \[5.2\times {{10}^{-4}}N\]
B) c \[2.5\times {{10}^{-3}}N\]
C) \[1.5\times {{10}^{-3}}N\]
D) \[3.5\times {{10}^{-4}}N\]
Correct Answer: B
Solution :
[b] Here \[{{q}_{1}}={{q}_{2}}=3.2\times {{10}^{-7}}c,r=60cm=0.6m\] Electrostatic force, \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[=\frac{3\times {{10}^{9}}{{\left( 3.2\times {{10}^{-7}} \right)}^{2}}}{{{\left( 0.6 \right)}^{2}}}=2.56\times {{10}^{-3}}N\]
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