A) \[2\times {{10}^{-2}}C\]
B) \[2\times {{10}^{-3}}C\]
C) \[2\times {{10}^{-4}}C\]
D) \[2\times {{10}^{-5}}C\]
Correct Answer: B
Solution :
[b] \[E=\frac{kQ}{{{r}^{2}}}\Rightarrow Q=\frac{E\times {{r}^{2}}}{k}=\frac{3\times {{10}^{6}}\times {{\left( 2.5 \right)}^{2}}}{9\times {{10}^{9}}}\] \[=2\times {{10}^{-3}}C\]You need to login to perform this action.
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