A) \[\frac{mg}{\sin \theta }\text{ and }\frac{qE}{\cos \theta }\]
B) \[\frac{mg}{\cos \theta }\text{ and }\frac{qE}{\sin \theta }\]
C) \[\frac{mg}{\cos \theta }\text{ and }\frac{qE}{\sin \theta }\]
D) \[\frac{mg}{qE}\]
Correct Answer: B
Solution :
[b] In equilibrium, \[T\cos \theta =mg\] ??..(1) \[T\sin \theta =qE\] ??..(2) From (1), \[T=\frac{mg}{\cos \theta }\] From (2), \[T=\frac{qE}{\sin \theta }\]You need to login to perform this action.
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