A) \[\left( {{\phi }_{2}}+{{\phi }_{2}} \right)\times {{\varepsilon }_{0}}\]
B) \[\left( {{\phi }_{2}}-{{\phi }_{2}} \right)\times {{\varepsilon }_{0}}\]
C) \[\left( {{\phi }_{1}}+{{\phi }_{2}} \right)\times {{\varepsilon }_{0}}\]
D) \[\left( {{\phi }_{1}}-{{\phi }_{2}} \right)\times {{\varepsilon }_{0}}\]
Correct Answer: D
Solution :
[d] \[\phi \,=E\,A\,\cos \,0{}^\circ \,=E\,\times \frac{\pi \,{{d}^{2}}}{4},\,\,\,\,\,\,\,\therefore \,E=\frac{4\,\phi }{\pi \,{{d}^{2}}}\]You need to login to perform this action.
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