A) +670kC
B) -670kC
C) -680kC
D) +680kC
Correct Answer: C
Solution :
[c] Given, Electric field \[E=150N/C\] Total surface charge carried by earth \[q=?\] According to Gauss's law. \[\phi =\frac{q}{{{\varepsilon }_{0}}}=EA\] or, \[q\,\,={{\in }_{0}}EA\,\,\,=\,\,{{\in }_{0}}E\pi {{r}^{2}}=8.85\times {{10}^{-12}}\times 150\times \]\[{{(6.37\times {{10}^{6}})}^{2}}.\]As electric field directed inward hence \[q=-\,680KC\]You need to login to perform this action.
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