A) \[\frac{2e}{{{\varepsilon }_{0}}}\]
B) \[\frac{e}{{{\varepsilon }_{0}}}\]
C) \[e{{\varepsilon }_{0}}\]
D) \[\frac{{{\varepsilon }_{0}}e}{4}\]
Correct Answer: A
Solution :
[a] According to Gauss's law total electric flux through a closed surface is \[\frac{1}{{{\varepsilon }_{0}}}\] times the total charge inside that surface. Electric flux, \[{{\phi }_{E}}=\frac{q}{{{\varepsilon }_{0}}}\] Charge on \[\alpha -\]particle=2e \[\therefore {{\phi }_{E}}=\frac{2e}{{{\varepsilon }_{0}}}\]
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