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NEET Chemistry Electrochemistry / विद्युत् रसायन Question Bank Self Evaluation Test - Electrochemistry

  • question_answer
    If 0.01 M solution of an electrolyte has a resistance of 40 ohms in a cell having a cell constant of \[0.4\text{ }c{{m}^{-1}},\] then its molar conductance in \[oh{{m}^{-1}}c{{m}^{2}}mo{{l}^{-1}}\] is

    A) \[{{10}^{2}}\]                        

    B) \[{{10}^{4}}\]  

    C) 10                                

    D) \[{{10}^{3}}\]

    Correct Answer: D

    Solution :

    [d] Molarity = 0.01 M ; Resistance = 40 ohm; Cell constant \[\frac{l}{A}=0.4\,c{{m}^{-1}}.\] Specific conductivity (k) \[=\frac{\text{cell constant}}{\text{resistance}}=\frac{0.4}{40}=0.01\text{ }oh{{m}^{-1}}\,c{{m}^{-1}}\] \[\text{Molar conductance}\left( {{\wedge }_{m}} \right)=\frac{1000\kappa }{Molarity}\]. \[=\frac{1000\times 0.01}{0.01}={{10}^{3}}oh{{m}^{-1}}\text{ }c{{m}^{2}}\text{ }mo{{l}^{-1}}\]


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