A) +0.3
B) 0.5
C) 1.5
D) \[-0.5\]
Correct Answer: A
Solution :
[a] Apply Nenst equation to the reaction \[Pb+S{{n}^{2+}}\to P{{b}^{2+}}+Sn\] \[{{E}_{cell}}=E{}^\circ +\frac{0.059}{2}\log \frac{[S{{n}^{2+}}]}{[P{{b}^{2+}}]}\] or \[\log \frac{[S{{n}^{2+}}]}{[P{{b}^{2+}}]}=\frac{0.01\times 2}{0.059}=0.3(\therefore {{E}_{cell}}=0)\] or \[\frac{[S{{n}^{2+}}]}{[P{{b}^{2+}}]}=anti\log \,0.3\]You need to login to perform this action.
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